- Set $G$ with one binary operation
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$x \cdot y \in G$
Closed operation:
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$x \cdot (y \cdot z) = (x \cdot y) \cdot z$
Associative operation:
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$1 \cdot x = x$
Operation has an identity:
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$x^{-1} \cdot x = 1$
Operation has an inverse:
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$x \cdot y = y \cdot x$
If commutative, group is Abelian: